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22 November, 14:13

CaCO3 + 2HCl - -> CaCl2 + CO2 + H2O In the reaction above, what mass of carbon dioxide is produced when 10 moles of HCl reacts with excess calcium carbonate?

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  1. 22 November, 17:20
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    According to the stoichiometry the CO2 formed is 1/2 the moles of H2O. So take the moles of CO2 as 5moles.

    n=m/M

    Where:

    n = mole

    m = mass

    M = molar mass

    Molar mass of CO2 = 44gmol^-1

    Therefore mass = 5mol * 44gmol^-1 = 220g
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