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7 December, 02:38

22.00 g of CO2 has a volume of 50.00 L and a pressure of 0.8210 atm. What must be the

temperature of the gas?

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Answers (1)
  1. 7 December, 05:49
    0
    T = 9.875K

    Explanation:

    The ideal gas Law is PV = nRT.

    P = Pressure

    V = Volume

    n = amount of substance

    R = 8.314 J / (K. mol)

    T = Temperature in Kelvin

    22g CO2

    CO2 Molar Mass = 44g/mol

    C = 12g/mol

    O = 16g/mol

    P = 0.8210atm

    V = 50L

    PV = nRT

    0.8210 x 50 = 8.314 x 0.5 x T

    41.05 = 4.157T

    T = 41.05/4.157

    T = 9.875K
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