How many moles of sodium chloride can react with 18.3 liters of fluorine gas at 1.2 atmospheres and 299 Kelvin?

1.79 mol.

Explanation:

For the balanced reaction:

2NaCl + F₂ → 2NaF + Cl₂.

It is clear that 2 mol of NaCl react with 1 mol of F₂ to produce 2 mol of NaF and 1 mol of Cl₂.

Firstly, we can get the no. of moles of F₂ gas using the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm (P = 1.2 atm).

V is the volume of the gas in L (V = 18.3 L).

n is the no. of moles of the gas in mol (n = ? mol).

R is the general gas constant (R = 0.0821 L. atm/mol. K),

T is the temperature of the gas in K (299 K).

∴ no. of moles of F₂ (n) = PV/RT = (1.2 atm) (18.3 L) / (0.0821 L. atm/mol. K) (299 K) = 0.895 mol.

Now, we can find the no. of moles of NaCl is needed to react with 0.895 mol of F₂:

Using cross multiplication:

2 mol of NaCl is needed to react with → 1 mol of F₂, from stichiometry.

? mol of NaCl is needed to react with → 0.895 mol of F₂.

∴ The no. of moles of NaCl needed = (2 mol) (0.895 mol) / (1 mol) = 1.79 mol.