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24 June, 10:19

How many moles of sodium chloride can react with 18.3 liters of fluorine gas at 1.2 atmospheres and 299 Kelvin?

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  1. 24 June, 12:07
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    1.79 mol.

    Explanation:

    For the balanced reaction:

    2NaCl + F₂ → 2NaF + Cl₂.

    It is clear that 2 mol of NaCl react with 1 mol of F₂ to produce 2 mol of NaF and 1 mol of Cl₂.

    Firstly, we can get the no. of moles of F₂ gas using the general law of ideal gas: PV = nRT.

    where, P is the pressure of the gas in atm (P = 1.2 atm).

    V is the volume of the gas in L (V = 18.3 L).

    n is the no. of moles of the gas in mol (n = ? mol).

    R is the general gas constant (R = 0.0821 L. atm/mol. K),

    T is the temperature of the gas in K (299 K).

    ∴ no. of moles of F₂ (n) = PV/RT = (1.2 atm) (18.3 L) / (0.0821 L. atm/mol. K) (299 K) = 0.895 mol.

    Now, we can find the no. of moles of NaCl is needed to react with 0.895 mol of F₂:

    Using cross multiplication:

    2 mol of NaCl is needed to react with → 1 mol of F₂, from stichiometry.

    ? mol of NaCl is needed to react with → 0.895 mol of F₂.

    ∴ The no. of moles of NaCl needed = (2 mol) (0.895 mol) / (1 mol) = 1.79 mol.
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