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8 November, 22:57

A gas has a volume of 5.00 L at 20.0oC. If the gas is compressed to 4.0 L, what is the new temperature of the gas in Kelvin?

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  1. 9 November, 01:35
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    Answer: 234.4K

    Explanation:

    Given that,

    Original volume of gas (V1) = 5.00 L

    Original temperature of gas (T1) = 20.0°C

    [Convert 20.0°C to Kelvin by adding 273

    20.0°C + 273 = 293K]

    New volume of gas (V2) = 4.0L

    New temperature of gas (T2) = ?

    Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

    V1/T1 = V2/T2

    5.00L/293K = 4.0L/T2

    To get the value of T2, cross multiply

    5.00L x T2 = 293K x 4.0L

    5.00L•T2 = 1172L•K

    Divide both sides by 5.00L

    5.00L•T2/5.00L = 1172L•K/5.00L

    T2 = 234.4K

    Thus, the new temperature of the gas is 234.4 Kelvin
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