Given 8.40 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100% yield?

11.07 g of CH₃CH₂CH₂COOC₂H₅

Solution:

The Balance Chemical Equation is as follow,

CH₃CH₂CH₂COOH + C₂H₅OH → CH₃CH₂CH₂COOC₂H₅ + H₂O

According to equation,

88.11 g (1 mol) Butanoic Acid produces = 116.16 g (1 mol) of Ethyl Butyrate

So,

8.40 g Butanoic Acid will produce = X g of Butyric Acid

Solving for X,

X = (8.40 g * 116.16 g) : 88.11 g

X = 11.07 g of Ethyl Butyrate