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24 February, 02:26

An aqueous 0.300 M glucose solution is prepared with a total volume of 0.150 L. The molecular weight of

glucose is 180.16

mol

What mass of glucose (in grams) is needed for the solution?

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Answers (1)
  1. 24 February, 03:36
    0
    We need 8.11 grams of glucose for this solution

    Explanation:

    Step 1: Data given

    Molarity of the glucose solution = 0.300 M

    Total volume = 0.150 L

    The molecular weight of glucose = 180.16 g/mol

    Step 2: Calculate moles of glucose in the solution

    Moles glucose = molarity solution * volume

    Moles glucose = 0.300 M * 0.150 L

    Moles glucose = 0.045 moles glucose

    Step 3: Calculate mass of glucose

    MAss glucose = moles glucose * molecular weight of glucose

    MAss glucose = 0.045 moles * 180.16 g/mol

    MAss glucose = 8.11 grams

    We need 8.11 grams of glucose for this solution
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