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26 July, 12:31

How many molecules of glycerol (c3h8o3; molecular mass = 92) are present in 1 l of a 0.5 m glycerol solution?

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  1. 26 July, 14:42
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    Answer is: 3.011·10²³ molecules of glycerol.

    c (C₃H₈O₃) = 0.5 M; concentration of glycerol solution.

    V (C₃H₈O₃) = 1 L; volume of glycerol.

    M (C₃H₈O₃) = 92 g/mol; molecular mass of glycerol.

    n (C₃H₈O₃) = c (C₃H₈O₃) · V (C₃H₈O₃),

    n (C₃H₈O₃) = 0.5 M · 1 L.

    n (C₃H₈O₃) = 0.5 mol, amount of substance.

    N (C₃H₈O₃) = n (C₃H₈O₃) · Na (Avogadro constant).

    N (C₃H₈O₃) = 0.5 mol · 6.022·10²³ 1/mol.

    N (C₃H₈O₃) = 3.011·10²³.
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