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27 June, 12:33

A 0.055 mol sample of formaldehyde vapor, CH2O, was placed in a heated 500 mL vessel and some of it decomposed. The reaction is CH2O (g) H2 (g) + CO (g) At equilibrium, the CH2O (g) concentration was 0.051 mol L-1. Calculate the value of Kc for this reaction?

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  1. 27 June, 13:00
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    Kc for this reaction is 0.06825

    Explanation:

    Step 1: Data given

    Number of moles formaldehyde CH2O = 0.055 moles

    Volume = 500 mL = 0.500 L

    At equilibrium, the CH2O (g) concentration = 0.051 mol

    Step 2: The balanced equation

    CH2O H2 + CO

    Step 3: Calculate the initial concentrations

    Concentration = moles / volume

    [CH2O] = 0.055 moles. 0.500 L

    [CH2O] = 0.11 M

    [H2] = 0M

    [CO] = 0M

    Step 4: The concentration at the equilibrium

    [CH2O] = 0.11 - X M = 0.051 M

    [H2] = XM

    [CO] = XM

    [CH2O] = 0.11 - X M = 0.051 M

    X = 0.11 - 0.051 = 0.059

    [H2] = XM = 0.059 M

    [CO] = XM = 0.059 M

    Step 5: Calculate Kc

    Kc = [H2][CO]/[CHO]

    Kc = (0.059 * 0.059) / 0.051

    Kc = 0.06825

    Kc for this reaction is 0.06825
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