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10 October, 13:55

What is the pressure of 0.500mol of gas at 12.2 L and 273K

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  1. 10 October, 17:39
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    P = 0.92 atm

    Explanation:

    Given dа ta:

    Pressure of gas = ?

    Number of moles = 0.500 mol

    Volume of gas = 12.2 L

    Temperature of gas = 273 K

    Solution:

    The given problem will be solve by using general gas equation,

    PV = nRT

    P = Pressure

    V = volume

    n = number of moles

    R = general gas constant = 0.0821 atm. L / mol. K

    T = temperature in kelvin

    Now we will put the values.

    P = nRT/v

    P = 0.500 mol * 0.0821 atm. L / mol. K * 273 K / 12.2 L

    P = 11.2 / 12.2 L

    P = 0.92 atm
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