Quicklime (CaO) is produced by the thermal decomposition of calcium carbonate (CaCO3). Calculate the volume of CO2 at STP produced from the decomposition of 152 g CaCO3 by the reaction.

CaCO3 - > CaO + CO2

V = 34.1 L

Explanation:

Given dа ta:

Mass of CaCO₃ = 152 g

Volume of CO₂ produced = ?

Solution:

Chemical equation:

CaCO₃ → CaO + CO₂

Number of moles of CaCO₃:

Number of moles = mass / molar mass

Number of moles = 152 g / 100 g/mol

Number of moles = 1.52 mol

Now we will compare the moles of CaCO₃ with CO₂

CaCO₃ : CO₂

1 : 1

1.52 : 1.52

Volume of CO₂:

PV = nRT

Standard temperature = 273 K

Standard pressure = 1 atm

R = 0.0821 atm. L/mol. K

Now we will put the value sin formula:

V = nRT/P

V = 1.52 mol * 0.0821 atm. L/mol. K * 273 K / 1 atm

V = 34.1 L