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27 October, 20:43

Beginning with commercial grade hydrochloric acid, 1.00 x 102 mL of a 12.4 M HCl is added to water to bring the total volume of the solution to 0.820L. What is the concentration of this new solution?

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  1. 27 October, 23:38
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    New concentration = 1.512 M

    Explanation:

    Using the equation for dilution;

    M1V1 = M2V2

    M1 = 12.4 M, V1 = 100 mL or 0.1 L

    M2 = ?, V2 = 0.820 L

    Therefore;

    M2 = M1V1/V2

    = (12.4 * 0.1) / (0.820L)

    = 1.512 M
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