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10 June, 19:07

a gas has a volume of 4.54 L at 1.65 atm and 75. I decrease celsius. At what pressure would the volume of the gas be increased to 5.33 L if the temperature is increased to 103 degrees Celsius?

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  1. 10 June, 21:54
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    The answer to your question is P2 = 1.52 atm

    Explanation:

    Data

    Volume 1 = V1 = 4.54 l

    Pressure 1 = P1 = 1.65 atm

    Temperature 1 = T1 = 75°C

    Volume 2 = V2 = 5.33 l

    Pressure 2 = P2 = ?

    Temperature 2 = 103°C

    Process

    1. - Convert temperature to °K

    Temperature 1 = 75 + 273 = 348°K

    Temperature 2 = 103 + 273 = 376°K

    2. - Use the combine gas law to find the final pressure

    P1V1/T1 = P2V2/T2

    -Solve for P2

    P2 = P1V1T2 / T1V2

    -Substitution

    P2 = (1.65 x 4.54 x 376) / (348 x 5.33)

    -Simplification

    P2 = 2816.62 / 1854.84

    -Result

    P2 = 1.52 atm
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