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10 June, 18:37

What is the empirical formula of a compound containing 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen?

C3H4N

C2H4N

C4H10N

C2H5N

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  1. 10 June, 19:07
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    = C3H4N

    Explanation:

    We are given; 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen.

    We first calculate the number of moles of each element.

    Carbon = 90g/12 g/mol

    = 7.5 moles

    Hydrogen = 11 g / 1 g/mol

    = 11 moles

    Nitrogen = 35 g / 14 g/mol

    = 2.5 moles

    The we get the mole ratio of the elements;

    = 7.5/2.5 : 11/2.5 : 2.5 / 2.5

    = 3 : 4.4 : 1

    = 3 : 4 : 1

    Therefore;

    The empirical formula will be; C3H4N
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