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19 November, 10:44

A rigid container holds a gas at a pressure of 55 kPa and a temperature of - 100.0*C. What will the pressure be when the temperature is increased to 200*C

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  1. 19 November, 12:40
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    P2 = 150.4 KPa

    Explanation:

    Gay-Lussac's Law:

    at constant volume, the pressure of a gas varies directly with the temperature

    P1/T1 = P2/T2

    ∴ P1 = 55 KPa

    ∴ T1 = - 100.0°C ≅ 173 K

    ∴ T2 = 200°C ≅ 473 K

    ⇒ P2 = ?

    P2 = T2*P1 / T1

    ⇒ P2 = (473 K) (55 KPa) / (173 K)

    ⇒ P2 = 150.4 KPa
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