If 95 grams of iron are needed to react with sulfur, how many grams of sulfur are involved

54.48g of S

Explanation:

First let us generate a balanced equation for the reaction. This is illustrated below:

Fe + S - > FeS

Molar Mass of Fe = 55.8g/mol

Molar Mass of S = 32g/mol

From the equation,

55.8g of Fe required with 32g of S.

Therefore 95g of Fe will require = (95 x 32) / 55.8 = 54.48g of S

I would say 190 grams