Ask Question
16 February, 06:01

How many grams of Magnesium Chloride (molar mass = 95.2 g/mole) will be needed to make 6.0 L of a 2.5 M MgCl2 solution?

+5
Answers (1)
  1. 16 February, 09:00
    0
    1428 g

    Explanation:

    2.5 M = 2.5 mol/L

    2.5mol/L*6.0 L = 15 mol MgCl2.

    Molar mass (MgCl2) = 24.3 g/mol + (2*35.5 g/mol) = 95.2 g/mol

    15 mol * 95.2 g/mol = 1428 g
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How many grams of Magnesium Chloride (molar mass = 95.2 g/mole) will be needed to make 6.0 L of a 2.5 M MgCl2 solution? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers