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Chemistry
Deborah Edwards
31 January, 09:34
What is the ph of 1.2 time 10 to the negitive 2
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Blossom
31 January, 10:01
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H⁺ = 1.2 x 10⁻²
pH = - log[H⁺]
= - log [ 1.2 x 10⁻²]
= - log1.2 + 2
= -.079 + 2
= 1.921.
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