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31 January, 09:34

What is the ph of 1.2 time 10 to the negitive 2

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  1. 31 January, 10:01
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    H⁺ = 1.2 x 10⁻²

    pH = - log[H⁺]

    = - log [ 1.2 x 10⁻²]

    = - log1.2 + 2

    = -.079 + 2

    = 1.921.
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