Balance the following chemical equation using the smallest set of integers. I₂ + Cl₂ + H₂O - --> HIO₂ + HCl The coefficient on H₂O is:

A. 1

B. 2

C. 5

D. 6

d. 6

Explanation:

Chemical equation:

I₂ + Cl₂ + H₂O → HIO₃ + HCl

Balanced chemical equation:

I₂ + 5Cl₂ + 6H₂O → 2HIO₃ + 10HCl

Step 1:

I₂ + Cl₂ + H₂O → HIO₃ + HCl

Reactant Product

I = 2 I = 1

Cl = 2 Cl = 1

H = 2 H = 2

O = 1 O = 2

Step 2:

I₂ + Cl₂ + H₂O → 2 HIO₃ + HCl

Reactant Product

I = 2 I = 2

Cl = 2 Cl = 1

H = 2 H = 3

O = 1 O = 6

Step 3:

I₂ + Cl₂ + 6H₂O → 2 HIO₃ + HCl

Reactant Product

I = 2 I = 2

Cl = 2 Cl = 1

H = 12 H = 3

O = 6 O = 6

Step 4:

I₂ + Cl₂ + 6H₂O → 2HIO₃ + 10HCl

Reactant Product

I = 2 I = 2

Cl = 2 Cl = 10

H = 12 H = 12

O = 6 O = 6

Step 5:

I₂ + 5Cl₂ + 6H₂O → 2HIO₃ + 10HCl

Reactant Product

I = 2 I = 2

Cl = 10 Cl = 10

H = 12 H = 12

O = 6 O = 6