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5 July, 10:19

at a constant temperature a gas is compressed from 4L to 1L. At 1L, the pressure of the gas is 98.2 kPa. What is the original pressure of this gas?

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  1. 5 July, 12:57
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    Answer: 24.6kpa

    Explanation:

    This is a classic case where Boyle's Law can be applied.

    The equation for Boyle's Law is given as: P1V1 = P2V2

    Where P1 = initial pressure

    P2 = final pressure

    V1 = initial volume

    V2 = final volume

    From the question, P1 = ?, P2 = 98.2kpa, V1 = 4L, V2 = 1L

    P1V1 = P2V2

    P1 x 4L = 98.2 kpa x 1L

    Make P1 subject of formula we then have:

    P1 = 98.2kpa X 1L / 4L

    = 24.6kpa
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