Consider the reaction of aluminum chloride with silver acetate. How ml of 0.250M aluminum chloride are required to react completely with 20ml of 0.500M silver acetate?

The balanced chemical equation would be as follows:

AlCl3 (aq) + 3AgC2H3O2 (aq) - > 3AgCl (s) + Al (C2H3O2) 3 (aq)

We are given the concentrations of the reactants. We use these values to calculate for the volume of aluminum chloride needed. We do as follows:

0.500 mol/L AgC2H3O2 (0.020 L) (1 mol AlCl3 / 3 mol AgC2H3O2) (1 L / 0.250 AlCl3) = 0.0133 L or 13.3 mL of AlCl3 solution is needed