A 3.682 g sample of kclo3 is dissolved in enough water to give 375. ml of solution. what is the chlorate ion concentration in this solution?

MKClO₃: 39g+35,5g + (16g*3) = 122,5 g/mol

1 mol - - 122,5g

X mol - - 3,682g

X = 3,682/122,5

X = 0,03 mol

375 ml = 0,375 l = 0,375 dm³

C = n/V

C = 0,03/0,375

C = 0,08 mol/dm³

[ClO₃-] = [KClO₃] = 0,08 mol/dm³