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7 May, 10:05

952 grams of ammonium carbonate are dissolved to make 1750 mL of solution

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  1. 7 May, 12:53
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    (%m/v) = mass of solute (in g) / volume of solution (in mL) x 100

    = 952 g (NH4) 2CO3 / 1750 mL x 100

    = 0.544 x 100

    (%m/v) = 54.4 g / mL or 54.4% concentration of ammonium carbonate

    solution
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