1. A mixture is found to contain 0.69 g SiO2, 1.05 g of cellulose, and 2.17 g of calcium carbonate. What is the mass percentage of SiO2 in this mixture?

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Chemistry

Cervantes

20 February, 02:04

1. A mixture is found to contain 0.69 g SiO2, 1.05 g of cellulose, and 2.17 g of calcium carbonate. What is the mass percentage of SiO2 in this mixture?

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Kristian Marquez · Answer 1

Mass percentage is another way of expressing concentration of a substance in a mixture. Mass percentage is calculated as the mass of a component divided by the total mass of the mixture, multiplied by 100%. It is calculated as follows:

% SiO2 = (0.69 g SiO2 / (0.69 g SiO2 + 1.05 g of cellulose + 2.17 g of calcium carbonate)) x 100% = 17.65% SiO2