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11 July, 10:55

A gas had a volume of 50L and a temperature of 650k. if the temperature increased to 2600k, what would be the volume be?

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  1. 11 July, 11:37
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    Assuming it's a perfect gas, we have PV=nRT hence V and T are proportional. T increased by 2600/650=4 times hence the volume will be 4 times bigger, which is 200L
  2. 11 July, 11:52
    0
    Charles' Law: V1 = V2 V2 = V1T2 V2 = (50L) (2600K) = 200L

    T1 T2 T1 (650K)
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