Calculate the mass of NaCl required to prepare 0.5 liters of a 2.5 molar solution of NaCl.

11

Na

22.99

Sodium

17

Cl

35.45

Chlorine

A. 37.1 g

B. 54.7 g

C. 73.1 g

D. 112.1 g

The answer is C. Here is the work:

Moles=molarity * volume

2.5 * 0.5 = 1.25mols of NaCI

Mm of NaCI = 58.442468/mol

Multiply the moles by the Mm and you get the grams

1.25 * 58.442468 = 73.1g