What volume does 8.5 g NH₃ occupy at STP?

a. 2.81 L

b. 5.61 L

c. 11.21 L

d. 22.41 L

e. 44.81 L

First, convert grams to moles by dividing 8.5 by the molar mass of NH₃ (N=14, H=1)

14+1+1+1=17

8.5/17=.5 moles NH₃

Multiply. 5 by the conversion factor of moles to L (22.4)

.5*22.4=11.2 L NH₃

11.2 is just 11.21 rounded down, so your answer is C) 11.21 L