Ask Question
19 January, 16:29

Determine the specific heat of a mayterial if a 35g sample of the material absorbs 48J as it is heated from 298K to 313K

+2
Answers (1)
  1. 19 January, 20:07
    0
    dа ta:

    m = 35g

    Q = 48 j

    T1 = 298K

    T2 = 313K

    Cs = ?

    Fórmula: Q = m*Cs * (T2 - T1) = > Cs = Q / [m (T2 - T1) ]

    Cs = 48 j / [35g (313K - 298K] = 0.0914 j / g*K = 91.4 j / kg*K
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Determine the specific heat of a mayterial if a 35g sample of the material absorbs 48J as it is heated from 298K to 313K ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers