In an experiment 150.0 grams of AsF3 were reacted with 180.0 g of CCl4 to produce AsCl3 and CCl2F2. The theoretical yield of CCl2F2, in grams, is

a) 141.5 grams

b) 206.2 grams

c) 137.5 grams

d) 104.4 grams

e) 152.6 grams

AsF₃:

M=132g/mol

m=150g

n = m/M = 150g/132g/mol = 1,14mol

CCl₄:

M=154g/mol

m=180g

n = m/M = 180g/154g/mol = 1,17mol

2AsF₃ + 3CCl₄ ⇒ 2AsCl₃ + 3CCl₂F₂

2mol : 3mol : 3mol

1,14mol : 1,17mol : 1,17mol

limiting reagent

0,78mol will react

CCl₂F₂:

n = 1,17mol

M = 121g/mol

m = nM = 1,17mol * 121g/mol = 141,57g

Answer a