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11 September, 00:28

A can of hairspray has a volume of 684 mL and contains 6.43 g of carbon dioxide as the propellant what is the pressure inside the can at 25°C

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  1. 11 September, 01:59
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    Use ideal gas equation

    pV = n RT = > p = nRT / V

    T = 25 + 273.15 K = 298.15 K

    V = 684 ml = 0.684 l

    R = 0.0821 atm * l / (K*mol)

    n = mass / molar mass =

    molar mass of CO2 = 12 g/mol + 2*16 g/mol = 44 g/mol

    n = 6.43 g / 44 g/mol = 0.14614 mol

    => p = 0.14614 mol * 0.0821 atm*l / (K*mol) * 298.15K / 0.684 l = 5.23 atm

    Answer: p = 5.23 atm
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