What is the mass, in grams, of 6.33 mol of nahco3?

1 mole of NaHCO3 contains 84.007g,

Therefore, to get the number of mass of 6.33 mol we multiply the number of moles and the relative formula mass.

That is; 6.33 moles * 84.007 g = 531.764 g

Hence the mass of 6.33 moles of NaHCO3 is 531.764 grams