A small hot-air balloon is filled with 1.00*106 L of air (d = 1.20 g/L). As the air in the balloon is heated, it expands to 1.12*106 L. What is the density of the heated air in the balloon?

The volume of air in the balloon is

V = 1 x 10⁶ L.

The density is

d = 1.20 g/L = 1.2 x 10⁻³ kg/L.

The mass of air is

m = V*d = (1 x 10⁶ L) * (1.2 x 10⁻³ kg/L) = 1.2 x 10³ kg

When the balloon s heated and the volume of air expands to 1.12 x 10⁶ L, the mass of air remains the same.

The new density, D, is given by

(1.2 x 10³ kg) = (D kg/L) * (1.12 x 10⁶ L)

D = (1.2 x 10³) / (1.12 x 10⁶) = 1.07 x 10⁻³ kg/L

Answer: 1.07 x 10⁻³ kg/L (or 1.07 g/L)