A balloon originally had a volume of 4.39 l at 44°c and a pressure of 729 torr. to what temperature must the balloon be cooled to reduce its volume to 3.78 l if the pressure is constant

The temperature of balloon that must be cooled to reduce its volume to 3.78l at constant pressure is calculated using the Charles law formula

that is V1/T1 = V2/T2

V1 = 4.39 L

T1 = 44 + 273 = 317K

v2 = 3.78L

T2=?

from the equation above T2 = V2 x T1/V1

= 3.78 x317/4.39 = 272.95 k which is approximate 273 k

T2 = 273 k or O c