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6 September, 12:48

What is the specific heat of a substance if 1560 cal are required to raise temperature of a 312 g substance by 15 degrees celsius?

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  1. 6 September, 13:51
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    The Specific Heat formula is:

    c = ΔQ / (m * ΔT)

    Where:

    c: Specific Heat, in J / (kg. K)

    ΔQ: Heat required for the temperature change, in J

    ΔT: Temperature change, in K

    m : Mass of the object, in kg

    So substitute the numbers in; Calories should be converted into joules

    c = 1560 (4.184) / (312*15)

    c = 1394.666
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