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11 December, 10:20

How many atoms of ca-46 would be found in a 25.0 g sample of naturally occurring calcium?

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  1. 11 December, 12:28
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    The number of ca-46 atoms found in 25.0 g sample is calculated as follows

    find the moles of Ca = 25/46 = 0.543 moles

    by use of Avogadro law

    1 mole = 6.02 x10^23 atoms what about 0.543 moles

    = 0.543moles/1mole x (6.02x10^23) atoms = 3.27 x10 ^23 atoms
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