Ask Question
13 July, 06:28

A 40.27 g sample of a substance is initially at 24.8 °c. after absorbing 2099 j of heat, the temperature of the substance is 148.5 °c. what is the specific heat (c) of the substance?

+4
Answers (1)
  1. 13 July, 10:11
    0
    Q = mCΔT

    Q is heat in joules, m is mass, C is specific heat, and delta T is change in temp

    2099 J = (40.27g) (C) (148.5 - 24.8) =.421 J / gram K
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A 40.27 g sample of a substance is initially at 24.8 °c. after absorbing 2099 j of heat, the temperature of the substance is 148.5 °c. what ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers