What would be the pOH of an HNO3 solution if the [H+] = 3.26 x 10-6 moles/liter?

8.51 would be the pOH of an HNo3 solution if the [H+] = 3.26 x 10^-6 moles/liter.

We are given with a compound, Nitric Acid (HNO3) solution, characterized as a strong acid. We are tasked to solve for it's corresponding mass pOH given [H+] = 3.26 x 10-6 moles/liter. Note that

14=pH+pOH

First we need to convert [H+] to pH by

pH=-log[H+]

pH=-log[3.26x10-6]

pH=5.49

Thus,

14=5.49+pOH

pOH=14-5.49=8.51

Therefore, the pOH of Nitric acid solution having a [H+] = 3.26 x 10-6 moles/liter is 8.51