The equilibrium concentrations were found to be [h2o]=0.250 m, [h2]=0.370 m, and [o2]=0.750 m. what is the equilibrium constant for this reaction

Question

Chemistry

Nylah Pratt

2 June, 22:41

The equilibrium concentrations were found to be [h2o]=0.250 m, [h2]=0.370 m, and [o2]=0.750 m. what is the equilibrium constant for this reaction

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Jayden Henry · Answer 1

The equilibrium constant for 2H2O---> 2H2 + O2 reaction is calculated as follows

Keg = { (H2) ^2 (O2) } / (H2o) ^2

that is{ (0.370^2) x (0.750) } / (0.250^2) = 1.643