Ask Question
6 October, 02:38

If it requires 37.5 mL of a 0.245 M HBr solution to neutralize 18.0 mL Mg (OH) 2, what is the concentration of the Mg (OH) 2 solution? 2 HBr + Mg (OH) 2 yields Mg (Br) 2 + 2 H2O

+5
Answers (1)
  1. 6 October, 04:53
    0
    2 HBr + Mg (OH) 2 yields Mg (Br) 2 + 2 H2O

    M1V1 = M2V2

    (0.245 M) (37.5 mL) = (M2) (18.0 mL)

    9.1875 = (M2) (18.0 mL)

    9.1875 / (18.0 mL) = (M2) (18.0 mL) / (18.0 mL)

    0.51041

    this is not the complete answer as the mol to mol ratio must be considered!

    For every 2 mols of HBr there is 1 mole of Mg (OH) 2; ratio = 2:1

    0.51041 / 2 = 0.25520

    M2 = 0.25520

    0.25520 M of Mg (OH) 2 solution
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “If it requires 37.5 mL of a 0.245 M HBr solution to neutralize 18.0 mL Mg (OH) 2, what is the concentration of the Mg (OH) 2 solution? 2 ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers