What is the mass of 560 L of nitrogen gas?

According to the ideal gas law one mole of an ideal gas occupies a volume of 22.4 L at standard temperature and pressure.

therefore, 1 mole of nitrogen will occupy a volume of 22.4 L

but 1 mole is equivalent to 28.04 g

thus, 28.04 g will occupy 22.4 L

then 560 L will contain a mass of (560/22.4) * 28.04 = 701 g

Hence, 560 L of nitrogen gas will have a mass of 701 g