During the combustion of 2.00 g of coal, the temperature of 500 g of water inside the calorimeter increased from 25.0°c to 43.7°c. the specific heat of water is 4.18 j/g·°c. how much heat did the reaction generate?

Answer is: 39,083kJ.

m (coal) = 2,00g.

m (water) = 500g.

ΔT = 43,7°C - 25°C = 18,7°C, difference at temperatures.

c (water) = 4,18 J/g·°C, specific heat of water

Q = m (water) ·ΔT·c (water), heat of reaction.

Q = 500g·18,7°C·4,18J/g·°C.

Q = 39083J = 39,083kJ.