A mixture of 6% disinfectant solution is to be made from 8% and 3% disinfectant solutions. how much of each solution should be used if 25 gallons of 6% solution are needed?

Question

Chemistry

Felix Terrell

15 April, 19:05

A mixture of 6% disinfectant solution is to be made from 8% and 3% disinfectant solutions. how much of each solution should be used if 25 gallons of 6% solution are needed?

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Answers (1)

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Alannah Byrd · Answer 1

Answer is: 10 gallons of 3% and 15 gallons of 8% solution.

V₁ + V₂ = 25 gallons.

0,03V₁ + 0,08V₂ = 0,06 · 25 gallons.

V₁ = 25 gallons - V₂.

0,03 · (25 gallons - V₂) + 0,08V₂ = 1,5 gallons.

0,75 gallons - 0,03V₂ + 0,08V₂ = 1,5 gallons.

0,05V₂ = 0,75 gallons.

V₂ = 0,75 gallons / 0,05.

V₂ = 15 gallons.

V₁ = 25 gallons - 15 gallons.

V₁ = 10 gallons.