Chromium metal can be produced from the high temperature reaction of Cr2O3 with silicon by the following reaction: Cr2O3 (s) + 2Al (l) - - > 2Cr (l) + Al2O3 (s) Calculate the number of grams of aluminum required to prepare 500.0g of chromium metal

To solve this problem, we need to know the molar mass of Aluminum and Chromium.

Aluminum = 27 g/mol

Chromium = 52 g/mol

Then, we do stoichiometry:

500.0 g Cr x (1/52 g/mol Cr) x (2 mol Al/2 mol Cr) x (27 g/mol Al)

= 259.62 g aluminum

Thus, you need 259.62 grams of reactant aluminum.