Ask Question
9 December, 19:20

Calculate the pressure drop in a duct (measured by a differential oil manometer) if the differential height between the two fluid columns is 3.2 cm and the density of oil is 860 kg/m3.

+4
Answers (1)
  1. 9 December, 21:04
    0
    The pressure drop is 269.7N/m^2

    Explanation:

    ∆P = ∆h * rho * g

    ∆h = 3.2cm = 3.2/100 = 0.032m, rho = 860kg/m^3, g = 9.8m/s^2

    ∆P = 0.032*860*9.8 = 269.7N/m^2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Calculate the pressure drop in a duct (measured by a differential oil manometer) if the differential height between the two fluid columns ...” in 📙 Engineering if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers