The specific volume of water vapor at 0.3 MPa, 160°C is 0.651 m3/kg. If the water vapor occupies a volume of 1.2 m3, determine the amount present, in kg.

1.84 kg

Explanation:

Data provided in the question:

Specific volume of water vapor at 0.3 MPa, 160°C = 0.651 m³/kg

Volume occupied by the water vapor = 1.2 m³

Now,

We know that the specific volume is given as:

specific volume = Volume : Mass

Therefore,

Mass = [Volume ] : [ specific volume ]

or

Mass = 1.2 : 0.651

or

Mass = 1.84 kg