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7 July, 12:55

A corn ethanol production plant receives 500,000.0 kg/day corn feedstock at a moisture content of 15.5% (wet basis). If all of this corn is converted into ethanol what is the theoretical volume of ethanol that this facility can produce per day? Assume that the starch content of corn grain is 68.5%. The density of ethanol is 789 kg/m3.

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  1. 7 July, 16:14
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    207 m³/day

    Explanation:

    Dry corn feed stock = 500000 * (100 - 15.5%) = 500000 * 84.5% = 500000 * 0.845 = 422500

    Starch yield = 68.5% * 422500 = 289412.5

    Glucose yield = 1.11 * 289412.5 = 321247.875 where 1.11 is the scarification factor of starch to glucose

    Ethanol yield = 0.51 * 321247.875 = 163836.416 where 0.51 is theoretical yield of ethanol from one mole of glucose

    density = mass / volume

    volume = mass / density = 163836.416 / 789 = 207 m³ / day
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