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15 April, 18:55

A permanent magnet DC motor has an armature resistance of 0.5 Ω and when a voltage of 120 V is applied to the motor it reaches a steady-state speed of rotation of 20rev/s and draws 40A. What will be:

(a) the power input to the motor?

(b) the power loss in the armature?

(c) the torque generated at that speed?

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Answers (1)
  1. 15 April, 19:22
    0
    12 N-m

    Explanation:

    The dc motor is operating at 24 V that is its terminal voltage V = 24 V

    Armature resistance = 0.2 ohm

    No load speed = 240 radian / sec

    For motor we know that as the motor is on no load so so

    Power developed in the motor

    Now we know that power = torque * angular speed

    So
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