Ask Question
17 March, 05:23

A30-mm diameter 1035 HR steel (tensile strength 500 MPa) shaft is used to transmit a steady 1 kW of power rotating at 600 rpm. For a safety factor of 3.0, calculate the magnitude of a completely reversed bending moment that can be applied to the shaft at a shoulder step where the diameter increases to 33-mm with a shoulder fillet radius of 5.25-mm. Use DE-Goodman criterion for safety under fatigue loading.

+4
Answers (1)
  1. 17 March, 08:13
    0
    See explanation for step by step procedure towards getting answer

    Explanation:

    Given that

    h = 30 mm

    h' = 25 mm

    Δh = 30 - 25 = 5 mm

    Initial width = b

    Final width = 1.04 b

    Roll radius, r = 300 mm

    Inlet velocity Vi = 77 m/min

    N = 45 RPM

    a)

    As we know that

    Δh = μ². r

    μ = Coefficient of friction

    r = roll radius

    By putting the values

    Δh = μ². r

    5 = μ² x 300

    μ=0.12

    b)

    From continuity equation

    Ai Vi = Vf

    Ai = Inlet area, Vi = inlet velocity

    = exit area, Vf = exit velocity

    b x h x Vi = 1.04 b x h' x Vf

    b x 30 x 77 = 1.04 b x 25 x Vf

    Vf=88.84 m/min

    c)

    Forward slip S given as

    V = Roller speed

    We know that

    V=84.82 m/min

    S=0.047
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A30-mm diameter 1035 HR steel (tensile strength 500 MPa) shaft is used to transmit a steady 1 kW of power rotating at 600 rpm. For a safety ...” in 📙 Engineering if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers