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8 July, 04:57

A wood pipe having an inner diameter of 3 ft. is bound together using steel hoops having a cross sectional area of 0.2 in^2. The allowable stress for the hoops is σallos=11.4 ksi. Determine the maximum spacing s along the pipe so that the pipe can resist an internal gauge pressure of 4 psi.

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  1. 8 July, 07:23
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    Answers:

    31.7 inches

    Explanation:

    Given:

    Diameter = 3ft

    Let D = Diameter

    So, D = 3ft. (Convert to inches)

    D = 3 * 12in = 36 inches

    Coss-sectional area of the steel = 0.2in²

    Gauge Pressure (P) = 4psi

    Stress in Steel (σ) = 11.4ksi

    Force in steel = ½ (Pressure * Projected Area)

    Area (A) = 2 * Force/Pressure

    Also, Area (A) = Spacing (S) * Wood Pipe Diameter

    Area = Area

    2*Force/Pressure = Spacing * Diameter

    Substitute values I to the above expression

    2 * Force / 4psi = S * 36 inches

    Also

    Force in steel (F) = Stress in steel (σ) * Cross-sectional area of the steel

    So, F = 11.4ksi * 0.2in²

    F = 11.4 * 10³psi * 0.2in²

    F = 2.28 * 10³ psi. in²

    So, 2 * Force / 4psi = S * 36 becomes

    2 * 2.28 * 10³/4 = S * 36

    S = 2 * 2.28 * 10³ / (4 * 36)

    S = 4560/144

    S = 31.66667 inches

    S = 31.7 inches (approximated)
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