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18 June, 22:30

You are an engineer in an electric-generation station. You know that the flames in the boiler reach a temperature of 1200 K and that cooling water at 300 K is available from a nearby river. What is the maximum efficiency your plant will ever achieve?

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  1. 19 June, 01:40
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    The maximum efficiency the plant will ever achieve is 75%

    Explanation:

    From the question given, we recall the following:

    Th flames in the boiler reaches a temperature of = 1200K

    the cooling water is = 300K

    The maximum efficiency the plant will achieve is defined as:

    Let nmax = 1 - Tmin / Tmax

    Where,

    Tmin = Minimum Temperature in plants

    Tmax = Maximum Temperature in plants

    The temperature of the cooling water = Tmin = 300K

    The temperature of the flames in boiler = Tmax = 1200k=K

    The maximum efficiency becomes:

    nmax = 1 - Tmin / Tmax

    nmax = 1 - 300 / 1200

    nmax = 1-1/4 = 0.75

    nmax = 75%
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