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29 February, 13:34

how many calories of heat energy are required to raise the temperature of 6 grams of water from 10 degrees celcius to 15 degrees celcius

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  1. 29 February, 14:36
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    Quantity of heat, Q = mc (t2 - t1), hence:

    273 * 103 J = 10 kg * c * (85 - 15) °C

    where c is the specific heat capacity,

    i. e. 273000 = 10 * c * 70

    from which, specific heat capacity, c =

    273000/10 * 70

    = 390 J / (kg °C
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